Engineering · Statics & Structural Analysis

Planar Truss Analysis Workbench Calculator

Screen planar truss determinacy and solve ideal joint equilibrium for member forces and pin-plus-roller reactions from entered geometry.

Engineering · Statics & Structural Analysis

Enter the engineering model

Explicit properties, geometry, units and assumptions
Each row: unique joint label, x, y.
Each row: start joint, end joint. Members are straight two-force elements.
Visual modelSchematic · not to scale
Statics & Structural Analysis: screen visual explanationA simplified diagram showing the relationship represented by the selected calculator mode. It is explanatory and not a fabrication, safety or scale drawing.member + reaction count versus joint equations
The diagram explains the selected relationship only. Dimensions, symbols and proportions are illustrative; use the entered values and stated assumptions for the calculation.

Keep every unit basis, sign convention, property source and idealization consistent. Values stay in this browser.

Engineering calculation result

Enter valid values to see the result.

Your entries are calculated in this browser and are not submitted to 365CALCS.COM.

Quick guide

How to use this calculator

  1. Choose the analysis mode that matches the physical model before entering values.
  2. Enter properties, geometry, loads, states and coefficients from one consistent unit and sign convention.
  3. Use the intermediate outputs to audit the relationship, then retain the stated idealization before applying it.

Calculation method

Transparent engineering model

Each joint supplies ΣFx=0 and ΣFy=0. Member forces are axial along member unit vectors; the square linear system solves all member forces and three reactions.

The calculator evaluates only the declared relationship and preserves visitor-entered assumptions rather than selecting materials, factors, components or standards.

Worked example

Worked example

A triangular truss with joints A(0,0), B(4,0), C(2,3), pin at A, vertical roller at B and 10 downward at C solves equal inclined-member compression.

Each joint supplies ΣFx=0 and ΣFy=0. Member forces are axial along member unit vectors; the square linear system solves all member forces and three reactions.

Supported inputs

Precision and limits

Analysis, not approval

Simple planar pin-jointed truss only. Geometry count is not a sufficient stability proof; buckling, connection eccentricity, deformation and capacity are excluded.

Standards and properties

Material properties, allowable values, load combinations, safety factors, correlations, manufacturer data, codes and jurisdictional requirements are not supplied automatically.

Units and precision

Use one consistent unit basis. Results retain working precision but cannot be more accurate than the entered measurements and properties.

Privacy

Entered engineering values and results stay in this browser and are not sent to analytics or third parties.