Engineering · Fluid Systems & Hydraulics

Hydraulic Power, Efficiency and Heat Loss Calculator

Reconcile pressure-flow hydraulic power, entered efficiency, shaft power and ideal loss converted to heat rate.

Engineering · Fluid Systems & Hydraulics

Enter the engineering model

Explicit properties, geometry, units and assumptions
  1. 1EnterProvide the known values
  2. 2CalculateResults update automatically
  3. 3VerifyReview the details and units
Try an example
Visual modelSchematic · not to scale
Fluid Systems & Hydraulics: pumpPower visual explanationA simplified diagram showing the relationship represented by the selected calculator mode. It is explanatory and not a fabrication, safety or scale drawing.shaft power → hydraulic powerloss becomes heat rate
The diagram explains the selected relationship only. Dimensions, symbols and proportions are illustrative; use the entered values and stated assumptions for the calculation.

Keep every unit basis, sign convention, property source and idealization consistent. Values stay in this browser.

Engineering calculation result

Enter valid values to see the result.

Your entries are calculated in this browser and are not submitted to 365CALCS.COM.

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Understand the fluid model

What this calculator is for

Reconcile pressure-flow hydraulic power, entered efficiency, shaft power and ideal loss converted to heat rate. It turns a fluid-system relationship into an auditable workflow without hiding the chosen coefficient, state, efficiency or boundary.

1Choose the solve direction and identify the physical control volume or component.
2Enter all pressures, flows, heads and dimensions in one consistent unit system.
3Check the reconciliation outputs and model boundary before using the result.

Visual explanation

The schematic highlights the entered states and the direction of flow, pressure, energy or volume change so the equation can be checked against the actual system.

The governing relationship

Ph=ΔpQ; for a pump Pin=Ph/η and loss=Pin−Ph; for a motor Pout=ηPh and loss=Ph−Pout.

Keep the boundary visible

Steady power arithmetic only. Leakage, mechanical losses, duty cycle, cooling, temperature rise and component ratings are excluded.

Quick guide

How to use this calculator

  1. Choose the analysis mode that matches the physical model before entering values.
  2. Enter properties, geometry, loads, states and coefficients from one consistent unit and sign convention.
  3. Use the intermediate outputs to audit the relationship, then retain the stated idealization before applying it.

Calculation method

Transparent engineering model

Ph=ΔpQ; for a pump Pin=Ph/η and loss=Pin−Ph; for a motor Pout=ηPh and loss=Ph−Pout.

The calculator evaluates only the declared relationship and preserves visitor-entered assumptions rather than selecting materials, factors, components or standards.

Worked example

Worked example

A 10 MPa pressure difference at 0.001 m³/s represents 10 kW of hydraulic power before efficiency.

Ph=ΔpQ; for a pump Pin=Ph/η and loss=Pin−Ph; for a motor Pout=ηPh and loss=Ph−Pout.

Supported inputs

Precision and limits

Analysis, not approval

Steady power arithmetic only. Leakage, mechanical losses, duty cycle, cooling, temperature rise and component ratings are excluded.

Standards and properties

Material properties, allowable values, load combinations, safety factors, correlations, manufacturer data, codes and jurisdictional requirements are not supplied automatically.

Units and precision

Use one consistent unit basis. Results retain working precision but cannot be more accurate than the entered measurements and properties.

Privacy

Entered engineering values and results stay in this browser and are not sent to analytics or third parties.