Genetics & Inheritance

Educational Pedigree Genotype Probability Calculator

Combine entered parent relationships and genotype evidence in a small, one-locus educational pedigree. Show how evidence changes every member's genotype probabilities.

Biology · experimental measurements

Condition a complete Mendelian pedigree model on entered evidence instead of multiplying unrelated probabilities.

Private calculations in your browser · explicit inputs and model boundaries
Example preview · Known heterozygote parentsPosterior heterozygote probability for each entered member
P1 · founder100 % Aa
P2 · founder100 % Aa
C1 · P1 + P250 % Aa

Bars summarize P(Aa) after conditioning on the whole pedigree. The ledger shows relationships, evidence and the complementary AA/aa probabilities; a bar is not a clinical risk.

  1. 1EnterProvide the known values
  2. 2CalculateResults update automatically
  3. 3VerifyReview the details and units
Try an example

0–1. Each unrelated founder receives explicit Hardy–Weinberg prior probabilities (1−q)², 2q(1−q), q².

One row: ID, parent 1 ID, parent 2 ID, evidence. List parents first. Founder parents are -,-. Evidence: ?, AA, Aa, aa, or A_ (AA or Aa). Maximum 10 members. Use fictional IDs.

Calculation result

Enter valid values to see the result.

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Understand the relationship

The reasoning behind the result

Relationships make the probability calculation joint

For every compatible assignment of AA, Aa and aa to the entered members, the calculator multiplies founder prior probabilities and Mendelian transmission probabilities. Evidence excludes incompatible assignments. Summing the remaining weights and normalizing gives a posterior distribution for each member.

An offspring can inform the parents, which in turn changes the distribution for another offspring. Treating each person's evidence independently would discard that shared structure. This implementation enumerates the bounded configuration space directly, up to 3¹⁰ assignments, using scaled log weights for small probabilities.

The founder assumption is a visible input

P(AA)=(1−q)²; P(Aa)=2q(1−q); P(aa)=q²

Each unrelated founder starts with the same user-entered a-allele frequency and Hardy–Weinberg prior. A known genotype then conditions that prior. Boundary q values can make some entered evidence impossible; the calculator reports the contradiction rather than inventing a posterior.

A_ means the exact set {AA, Aa} under complete dominance and full penetrance. It is not a clinical unaffected category. The probability of the evidence measures its weight in the stated model and does not measure whether the pedigree is true.

Posterior uncertainty must stay visible

A dominant-class offspring of Aa × Aa is not equally likely to be AA or Aa. The original weights are 1/4 and 1/2; excluding aa and dividing by 3/4 yields 1/3 and 2/3. The result keeps all three probabilities for every member.

The same listed ancestor may contribute through more than one relationship path, because each member is represented once in the joint model. Founders are assumed unrelated. Missing parents must be represented explicitly as distinct unknown founders rather than silently supplying a population average.

Follow the numbers

Conditioning on a dominant expression class

  1. Two parents have known genotype Aa. Before offspring evidence, their offspring has AA 25%, Aa 50%, aa 25%.
  2. Evidence A_ excludes aa but retains both AA and Aa.
  3. The retained conditional probability is 25% + 50% = 75%.
  4. Normalize: P(AA | A_)=25/75=1/3 and P(Aa | A_)=50/75=2/3.

The offspring remains uncertain: one-third AA and two-thirds Aa. Dominant expression is not proof of a homozygous genotype.

Quick guide

How to use this calculator

  1. Use fictional records for an educational autosomal, two-allele exercise and enter the founder-frequency assumption.
  2. List each founder with -,- parents, then descendants with two distinct already-listed parent IDs.
  3. Enter known genotype, dominant-class evidence A_, or ? for unknown. Read all posterior genotype probabilities, not just the most likely state.

Calculation method

Calculation and interpretation

Condition a complete Mendelian pedigree model on entered evidence instead of multiplying unrelated probabilities.

P(genotype configuration | evidence) ∝ founder prior product × offspring transmission product × evidence compatibility; member probabilities sum over all compatible configurations.

Worked example

Conditioning on a dominant expression class

The offspring remains uncertain: one-third AA and two-thirds Aa. Dominant expression is not proof of a homozygous genotype.

P(genotype configuration | evidence) ∝ founder prior product × offspring transmission product × evidence compatibility; member probabilities sum over all compatible configurations.

Supported inputs

Precision and limits

Educational inheritance model

Uses a diploid, two-allele model with equal segregation. It does not interpret a person's genetic test, assess disease or reproductive risk, establish parentage, or predict a real offspring's traits. Linkage, selection, incomplete penetrance, mutation, viability differences and environmental effects are excluded.

Small exact educational model

At most ten members, one autosomal locus, two alleles, unrelated Hardy–Weinberg founders with the same entered frequency, error-free genotype/evidence and fully penetrant expression. No clinical penetrance, disease prevalence, genetic test error, ascertainment, mutation or pedigree verification is supplied.

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