Genetics & Inheritance

Multiple-Offspring Inheritance Probability Calculator

Calculate exact-count and count-range probabilities from an entered per-offspring probability or a target genotype in a Mendelian cross.

Biology · experimental measurements

Separate a single-offspring probability from the distribution of counts across independent offspring.

Private calculations in your browser · explicit inputs and model boundaries
Example preview · Exactly one recessiveHow the matching-offspring count is distributed
0010.5121.1231.6342.24Point 1: 0, 31.640625Point 2: 1, 42.1875Point 3: 2, 21.09375Point 4: 3, 4.6875Point 5: 4, 0.390625Matching offspring countExact-count probability (%)

Each dot is a discrete count probability, not a continuous density. The requested inclusive count interval is 1 to 1; the ledger marks every included count.

  1. 1EnterProvide the known values
  2. 2CalculateResults update automatically
  3. 3VerifyReview the details and units
Try an example

Use AA, Aa or aa; add Bb and Cc pairs for up to three independent loci. Example: AaBb.

Use the same loci, in the same order. Genotypes are known model inputs, not inferred from appearance.

Examples: aa, AaBb, A_bb or A_B_. A_ includes AA and Aa. All loci must be specified.

Whole number from 1 to 1000.

For an exact count, enter the same minimum and maximum.

Calculation result

Enter valid values to see the result.

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Understand the relationship

The reasoning behind the result

First define one matching outcome

The event might be genotype aa, exact multilocus genotype AaBb, or an expression pattern such as A_bb. The underscore stands only for the second allele in a complete-dominance class. All unspecified biological details remain outside the model.

If a probability comes from another model, enter it directly. Multiplying arbitrary parental probabilities is not a substitute for defining the offspring event.

An exact count includes every ordering

C(n,k) = n! / [k!(n−k)!]

One specific ordering of k matches and n−k nonmatches has probability p^k(1−p)^(n−k). The binomial coefficient counts how many orderings produce that same total. Range probabilities add the mutually exclusive exact-count cases, including both endpoints.

For at least one match, a useful independent check is 1−(1−p)^n. For no matches, use (1−p)^n. These complements are not the probability of exactly one match.

Independence is conditional on known assumptions

The model holds p fixed across offspring and treats outcomes as independent under that p. If parental genotypes are uncertain, the same hidden parental state affects all siblings; averaging p first and using one binomial can be wrong. Analyze each parental scenario separately or use an appropriate joint model.

Expected count np and standard deviation √[np(1−p)] describe the distribution; neither is a promised family outcome or a clinical assessment.

Follow the numbers

Exactly one aa outcome among four offspring

  1. Aa × Aa gives P(aa)=1/4.
  2. A specified ordering with one aa and three other outcomes has probability 0.25 × 0.75³ = 0.10546875.
  3. There are C(4,1)=4 possible positions for the matching offspring.
  4. Multiply: 4 × 0.10546875 = 0.421875, or 42.1875%.

Exactly one match has probability 42.1875%; at least one has the different probability 1−0.75⁴ = 68.359375%.

Quick guide

How to use this calculator

  1. Enter a known fixed probability or derive one from two known genotypes and a target pattern.
  2. Set the number of independent offspring and the inclusive count interval. Use equal endpoints for an exact count.
  3. Compare the interval probability with the expected count, variability and full count distribution.

Calculation method

Calculation and interpretation

Separate a single-offspring probability from the distribution of counts across independent offspring.

P(K=k) = C(n,k) p^k (1−p)^(n−k); P(L≤K≤U) = sum from k=L to U; E[K]=np.

Worked example

Exactly one aa outcome among four offspring

Exactly one match has probability 42.1875%; at least one has the different probability 1−0.75⁴ = 68.359375%.

P(K=k) = C(n,k) p^k (1−p)^(n−k); P(L≤K≤U) = sum from k=L to U; E[K]=np.

Supported inputs

Precision and limits

Educational inheritance model

Uses a diploid, two-allele model with equal segregation. It does not interpret a person's genetic test, assess disease or reproductive risk, establish parentage, or predict a real offspring's traits. Linkage, selection, incomplete penetrance, mutation, viability differences and environmental effects are excluded.

Fixed independent trials

No family-level uncertainty, shared viability effects or dependence between outcomes is inferred. The full distribution is limited to 1000 offspring; extremely small tails may round below floating-point range.

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